- #1

- 37

- 0

## Homework Statement

A string passing over a pulley has a 3.80-kg mass hanging from one end and a 3.15-kg mass hanging from the other end. The pulley is a uniform solid cylinder of radius 4.0 cm and mass 0.80 kg. If the bearings of they pulley were frictionless, what would be the acceleration of the two masses?

## Homework Equations

I=0.5mr

^{2}

a=rα

Ʃτ=Iα

τ=Fr

T

_{1}-m

_{A}g=m

_{A}a

m

_{B}g-T

_{2}=m

_{B}a

## The Attempt at a Solution

I tried rearranging the bottom two equations into the form:

a=(T

_{1}-m

_{A}g)/m

_{A}

a=(m

_{B}g-T

_{2})/m

_{B}

I then plugged variables into the following equation:

Ʃτ=0.5mr

_{2}α

(T

_{2}-T

_{1})r=0.5mr

_{2}α

(T

_{2}-T

_{1})r=0.5mr

_{2}(a/r)

This equation then simplifies to:

a=(2T

_{2}-2T

_{1})/m

This is where I'm stuck. How do I proceed from here? Thanks.